Answered

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A5 kg box is at the top of a 2.7 m tall frictionless incline as shown in the diagram. It slides to the bottom of the incline, reaching a speed of 7.3m / s . What is the box's kinetic energy at the bottom of the incline? Whats the boxs ptential energy at the top of the incline?

A5 Kg Box Is At The Top Of A 27 M Tall Frictionless Incline As Shown In The Diagram It Slides To The Bottom Of The Incline Reaching A Speed Of 73m S What Is The class=

Sagot :

ANSWER:

Kinetic energy: 133.2 J

Potential energy: 132.3 J

STEP-BY-STEP EXPLANATION:

Gven:

Mass (m) = 5 kg

Height (h) = 2.7 m

Speed (v) = 7.3 m/s

We calculate the kinetic energy and the potential energy using the respective formula in each case, as follows:

[tex]\begin{gathered} E_k=\frac{1}{2}\cdot m\cdot v^2=\frac{1}{2}(5)(7.3)^2=133.2\text{ J} \\ \\ E_p=m\cdot g\cdot h=(5)(9.8)(2.7)=132.3\text{ J} \end{gathered}[/tex]

Therefore, the kinetic energy is equal to 133.2 joules and the potential energy is equal to 132.3 joules.

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