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Rhombus ABCD with vertices A(1,0), B(6,-2), C(8,-7), and D(3,-5); 90° counterclockwise rotation about the origin

Sagot :

Given data:

The given coordinates of Rhombus are A(1,0), B(6,-2), C(8,-7), and D(3,-5).

The coordinate of a point after 90 degrees counterclockwise rotation is,

[tex](x,\text{ y)}\rightarrow(-y,x)[/tex]

The final coordinate of Rhombus are,

[tex]\begin{gathered} A(1,0)=A^{\prime}(0,\text{ 1)} \\ B(6,\text{ -2)=B'(2, 6)} \\ C(8,\text{ -7)=C'(7},\text{ 8)} \\ D(3,\text{ -5)=D'(5, 3)} \end{gathered}[/tex]

Thus, the final coordinate of Rhombus are A'(0,1), B'(2, 6), C'(7, 8) and D'(5, 3).

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