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You phone a plumber for a quote on fixing your leaky pipes. You are quoted $190 for the service call and $90 per hour for the work. You are on a budget and can afford no more then $460 . Write an inequality to find the number of hours of work h you can afford. ( assume h greater than or equal 0) then solve the inequality

Sagot :

We want to find h which represents the number of hours of work that you can afford.

From the information given,

The charge per hour of work is $90. This means that the charge for h hours of work is

90 x h = 90h

The service fee is $190. This is a constant fee that must be paid irrespective of the number of hours. Thus, the total cost of h hours of work is

90h + 190

Again, you are on a budget and can afford no more then $460. This means that the amount that you can spend is less than or equal to $460. the symbol for representing 'less than or equal to' is '≤'

Therefore, the inequality that will be used to find the number of hours of work h you can afford is

90h + 190 ≤ 460

To solve the inequality, we would subtract 190 from both sides of the inequality. We have

90h + 190 - 190 ≤ 460 - 190

90h ≤ 270

We would divide both sides of the inequality by 90. We have

90h/90 ≤ 270/90

h ≤ 3

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