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Sagot :
[tex]\begin{gathered} f(x)=4x+1 \\ g(x)=x^2-5 \end{gathered}[/tex]
We need to find g(x)/f(x) so we will put them over each other as a fraction
[tex]\frac{g(x)}{f(x)}=\frac{x^2-5}{4x+1}\text{ , x}\ne\frac{-1}{4}[/tex]In any algebraic fraction, denominators can not be zero, so we avoid any values make it equal to zero like -1/4 in our question
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