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Use a calculator to help answer the question, Show that the point (6,1) is equidistant from points (9,0) and (3,0).The distance from (6,1) to (9,0) and the distance from (6,1) to (3,0) are both [ ] . Thus, (6,1) is equidistant from the two points.

Sagot :

First find the distance from (3,0) to (6,1)

We will use the distance formula

d = sqrt( (x2-x1)^2 + ( y2-y1)^2)

= sqrt( ( 6-3)^2 + ( 1-0)^2)

= sqrt( 3^2 + 1^2)

= sqrt( 9+1)

= sqrt(10)

Now we can find the distance between ( 6,1) and (9,0)

We will use the distance formula

d = sqrt( (x2-x1)^2 + ( y2-y1)^2)

= sqrt( ( 9-6)^2 + (0-1)^2)

= sqrt( 3^2+ (-1)^2)

= sqrt( 9+1)

= sqrt(10)

The distance is sqrt(10)

[tex]\sqrt[]{10}[/tex]

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