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Sagot :
[tex]\begin{gathered} \frac{\sqrt[]{3}}{2}\text{ is a known value, and the main angle that has:} \\ \sin (\theta)=\frac{\sqrt[]{3}}{2}\text{ is }\theta=60\text{ degrees}=\frac{\pi}{3} \end{gathered}[/tex]
Then, since arcsin is a function:
[tex]\begin{gathered} R\rightarrow\mleft\lbrace-1;\text{ 1}\mright\rbrace \\ We\text{ take only value }\theta=\frac{\pi}{3},\text{ without the periodic values.} \\ \text{That means,} \\ \arcsin (\frac{\sqrt[]{3}}{2})=60\text{ degrees= }\frac{\pi}{3} \end{gathered}[/tex]
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