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In the equation IX=b, if b<0, then how many solutions are there for x? Think about this: b is a number less than 0

Sagot :

If we assume x and b are real numbers:

|x| = √(x²)

So:

√(x²) = b

Where b<0

x will be always positive, because every number squared is positive

So, the left hand side of the equation will be positive. And since the right hand side of the equation will be always negative, because they tell us that b<0, we can conclude that it is absurd:

√(x²) ≠ b

Therefore, no solutions exist

The answer is Zero

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