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Sagot :
the First, we figure out the equation of the line.
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]We pick point (8,27) as point 1 and (10,35) as point 2.
Therefore equation of line =
[tex]\begin{gathered} \frac{y-27_{}}{x-8_{}}=\frac{35-27_{}}{10-8_{}} \\ \frac{y-27_{}}{x-8_{}}=\frac{8}{2} \end{gathered}[/tex]Cross multiplying, we have
8x -64 = 2y - 54
Adding 54 to both sides, we have:
8x - 10 = 2y
Dividing both sides by 2, we have:
y = 4x -5
Next, we substitute the value of x with 12 to get:
y = 4(12) - 5
y = 48 - 5
y = 43
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