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Sagot :
We have to find the solution for this equations.
a) -30 = -10(q-1)
[tex]\begin{gathered} -30=-10(q-1) \\ q-1=\frac{-30}{-10} \\ q-1=3 \\ q=3+1 \\ q=4 \end{gathered}[/tex]b) 6+(c+8) = 13
[tex]\begin{gathered} 6+(c+8)=13 \\ c=13-6-8 \\ c=-1 \end{gathered}[/tex]c) 6-(c+8)=13
[tex]\begin{gathered} 6-(c+8)=13 \\ 6-13=c+8 \\ -7=c+8 \\ -7-8=c \\ c=-15 \end{gathered}[/tex]d) -(c-4)=13
[tex]\begin{gathered} -(c-4)=13 \\ c-4=-13 \\ c=-13+4 \\ c=-9 \end{gathered}[/tex]f) -36= -3(2-5m)
[tex]\begin{gathered} -36=-3(2-5m) \\ \frac{-36}{-3}=2-5m \\ 12=2-5m \\ 5m=2-12 \\ 5m=-10 \\ m=\frac{-10}{5} \\ m=-2 \end{gathered}[/tex]g) 4-10(n+4)=-56
[tex]\begin{gathered} 4-10\mleft(n+4\mright)=-56 \\ 4+56=10(n+4) \\ 60=10(n+4) \\ \frac{60}{10}=n+4 \\ 6=n+4 \\ n=6-4 \\ n=2 \end{gathered}[/tex]
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