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Solve for y means we need to isolate y from the equation:
We need to use inverse operations to solve equations:
[tex]\begin{gathered} 5x-8y=40 \\ -8y=40-5x \\ y=\frac{-5}{-8}x+\frac{40}{-8} \\ y=\frac{5}{8}x-5 \end{gathered}[/tex]