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Find the equivalent resistance of thiscircuit.R₁www400 ΩIR₂600 ΩReq = [?] 2R3www500 Ω

Find The Equivalent Resistance Of ThiscircuitRwww400 ΩIR600 ΩReq 2R3www500 Ω class=

Sagot :

We are given the following information.

Resistor: R₁ = 400 Ω

Resistor: R₂ = 600 Ω

Resistor: R₃ = 500 Ω

We are asked to find the equivalent resistance of the given circuit.

Notice that the resistors R₁ and R₂ are in parallel and this parallel combination is in series with resistor R₃.

First, let us find the parallel resistance of R₁ and R₂.

[tex]R_p=\frac{R_1\times R_2}{R_1+R_2}=\frac{400\times600}{400+600}=\frac{240000}{1000}=240\;\Omega[/tex]

Finally, let us find the series resistance of Rp and R₃.

[tex]\begin{gathered} R_{eq}=R_p+R_3 \\ R_{eq}=240+500 \\ R_{eq}=740\;\Omega \end{gathered}[/tex]

Therefore, the equivalent resistance of the given circuit is 740 Ω.

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