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What is the volume of 0.110 g of C2H2F4 vapor at 0.887 atm and 34.0°C?Answer in units of L.Leave all the numbers after the decimal point (No usage of significant figures)

What Is The Volume Of 0110 G Of C2H2F4 Vapor At 0887 Atm And 340CAnswer In Units Of LLeave All The Numbers After The Decimal Point No Usage Of Significant Figur class=

Sagot :

Assume that C₂H₂F₄ vapor is an ideal gas and use the ideal gas law to find the volume of the vapor.

First, use the molecular mass of the compound to find the number of moles present in 0.110g of the compound.

[tex]0.110g\cdot\frac{1mol}{102.03g}=0.00108mol[/tex]

Convert the temperature in celsius to kelvin:

[tex]K=34+273.15=307.15[/tex]

Use the ideal gas law and solve it for V:

[tex]\begin{gathered} P\cdot V=n\cdot R\cdot T \\ V=\frac{n\cdot R\cdot T}{P} \end{gathered}[/tex]

Replace for the known values (R, the ideal gas constant is 0.082 atmL/molK):

[tex]\begin{gathered} V=\frac{0.00108mol\cdot0.082\frac{atmL}{molK}\cdot307.15K}{0.887atm} \\ V=0.0306L \end{gathered}[/tex]

The volume of the vapor is 0.0306L.

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