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Recall the definition of the sine of an angle on a right triangle:
[tex]\sin (A)=\frac{a}{c}[/tex]On the other hand, according to this diagram, the values for tan(A) and cos(A) are given by:
[tex]\begin{gathered} \cos (A)=\frac{b}{c} \\ \tan (A)=\frac{a}{b} \end{gathered}[/tex]Since 180≤A≤270, the right triangle that corresponds to the angle A on the coordinate plane looks as follows:
Where a and b are negative distances.
Since sin(A)=-4/7, we can assume that a=-4 and c=7. Use the Pythagorean Theorem to find the exact value of b:
[tex]\begin{gathered} a^2+b^2=c^2 \\ \Rightarrow(-4)^2+b^2=7^2 \\ \Rightarrow16+b^2=49 \\ \Rightarrow b^2=49-16 \\ \Rightarrow b^2=33 \\ \Rightarrow|b|=\sqrt[]{33} \end{gathered}[/tex]We know that b should be negative. Then:
[tex]b=-\sqrt[]{33}[/tex]Substitute b=-sqrt(33) and c=7 to find the exact values for cos(A) and tan(A):
[tex]\begin{gathered} \cos (A)=-\frac{\sqrt[]{33}}{7} \\ \tan (A)=\frac{-4}{-\sqrt[]{33}}=\frac{4\cdot\sqrt[]{33}}{33} \end{gathered}[/tex]Therefore, the exact values for cos(A) and tan(A) are:
[tex]\begin{gathered} \cos (A)=-\frac{\sqrt[]{33}}{7} \\ \tan (A)=\frac{4\cdot\sqrt[]{33}}{33} \end{gathered}[/tex]
