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Use substitution to solve.Solve the first equation for y and substitute it into the second equation. The resulting equati

Use Substitution To SolveSolve The First Equation For Y And Substitute It Into The Second Equation The Resulting Equati class=

Sagot :

The first equation is given as,

[tex]\begin{gathered} 2X^2\text{ = 5 +Y} \\ Y\text{ = }2X^2\text{ - 5\_\_\_\_\_\_\_(1)} \end{gathered}[/tex]

The second equation is given as,

[tex]4Y\text{ = }-20\text{ }+8X^2_{_{_{_{}}}}\text{ \_\_\_\_\_\_\_\_\_(2)}[/tex]

Substituting equation ( 1 ) in equation (2),

[tex]4(\text{ }2X^2\text{ - 5) = }-20\text{ }+8X^2_{_{_{_{}}}}\text{ }[/tex]

Simplifying further,

[tex]8X^2-20\text{ = -20 + }8X^2[/tex]

Thus the required answer is

[tex]8X^2-20\text{ = -20 + }8X^2[/tex]

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