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Given data:
The first end point of the diameter is (-14, 1).
The second end point of the diameter is (-10, 9).
The centre of the circel is,
[tex]\begin{gathered} x=\frac{-14-10}{2} \\ =\frac{-24}{2} \\ =-12 \\ y=\frac{1+9}{2} \\ =5 \end{gathered}[/tex]The diameter of the circle is,
[tex]\begin{gathered} d=\sqrt[]{(-10+14)^2+(9-1)^2} \\ =\sqrt[]{16+6}4 \\ =4\sqrt[]{5} \end{gathered}[/tex]The radius is,
[tex]\begin{gathered} r=\frac{4\sqrt[]{5}}{2} \\ =2\sqrt[]{5} \end{gathered}[/tex]The equation for the circle is,
[tex]\begin{gathered} (x-(-12))^2+(y-5)^2=(2\sqrt[]{5})^2 \\ (x+12)^2+(y-5)^2=20 \end{gathered}[/tex]Thus, the equation for the circle is (x+12)^2 +(y-5)^2 =20.