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A wheel of radius 30.0 cm is rotating at a rate of 2.30 revolutions every 0.0810 s.Through what angle does the wheel rotate in 1.00 s?What is the linear speed of a point on the wheel’s rim?What is the wheel’s frequency of rotation?

Sagot :

Given data

*The given radius of the wheel is r = 30.0 cm = 0.30 m

*Rate of rotation is 2.30 revolutions every 0.0810 s

The angle of the wheel rotates in one second is calculated as

[tex]\begin{gathered} \theta=(2.30\times2\pi)\times\frac{1}{0.0810} \\ =178.32\text{ radian} \end{gathered}[/tex]

Hence, the angle of the wheel rotating in one second is 178.32 radian

The formula for the linear speed of a point on the wheel's rim is given as

[tex]v=r\omega[/tex]

Substitute the known values in the above expression as

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