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What is the molarity of a solution after 14.38 mL of 1.950 M NaCI solution is distilled into a total of 533.98 mL solution?

Sagot :

To answer this question we have to use the rule of dilutions:

[tex]C1V1=C2V2[/tex]

Where C1 and C2 are the initial and final concentrations and V1 and V2 are the initial and final volumes, respectively. In this case we have to find C2 and the other values are given:

[tex]\begin{gathered} C2=\frac{C1V1}{V2} \\ C2=\frac{14.38mL\cdot1.950M}{533.98mL} \\ C2=0.052M \end{gathered}[/tex]

It means that the answer is 0.052M.

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