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find the area of a sector with a central angle of 1/2 pi and a radius of 11.3

Sagot :

First, let's find the length of an arc:

[tex]L=\text{r}\cdot\theta=11.3\cdot\frac{\pi}{2}=\frac{113\pi}{20}[/tex]

Therefore, the area is:

[tex]A=\frac{rL}{2}\approx100.3[/tex]

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