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DCF = FB and AE = EBCB = 38 and AB = 22DE = [?]EBFLLEnter

DCF FB And AE EBCB 38 And AB 22DE EBFLLEnter class=

Sagot :

Given

Also, CF = FB and AE = EB, CB = 38 and AB = 22.

To find the length of DE.

Explanation:

It is given that,

Also, CF = FB and AE = EB, CB = 38 and AB = 22.

That implies,

By using midpoint theorem of triangle, we have,

[tex]DE=\frac{1}{2}BC[/tex]

Therefore,

[tex]\begin{gathered} DE=\frac{1}{2}\times38 \\ =19 \end{gathered}[/tex]

View image OndreK448634
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