Answered

IDNLearn.com offers a seamless experience for finding and sharing knowledge. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.

Need help with this homework Part 2) construct the line that is perpendicular to the directrix and passes through the focus. This line will be the axis of symmetry of the para bola what are the coordinates of the point of intersection,A, of the access of symmetry and directrix of the parabola

Need Help With This Homework Part 2 Construct The Line That Is Perpendicular To The Directrix And Passes Through The Focus This Line Will Be The Axis Of Symmetr class=

Sagot :

After following the instructions in part A, the result is

In general, the equation of a horizontal line is y=a, with 'a' a constant. In our case, the line has to be 6 units below F; then y=4-6=-2. The equation of the directrix is y=-2

Part 2)

In Geogebra, go to Tools->Construct->Perpendicular Line; then, click on point F and line y=-2. A new line should appear on your screen, then go to Tools->Points->Intersect and select both lines. After naming the intersection point as 'A', the result is

The answer to part 2) is A=(6,-2)

View image RoselieJ197530
View image RoselieJ197530
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.