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The length of a rectangle is 4 in longer than its width. If the perimeter of the rectangle is 362 in, find it's area.

Sagot :

The length of a rectangle is 4 in longer than its width, which means

Length = 4 in + width

P = 362 in = 2L + 2W

362in = 2(4 in + W) + 2W = 8in+2W+2W = 8in + 4W

362in = 8in + 4W

Solve for W

362 in - 8in = 4W

354 = 4W

354/4 = W

88.5 = W

Replace W in the Length

Length = 4 in + W

Length = 4 in + 88.5in

Length = 92.5in

The formula for the area is A = Length * Width = L * W

Replace the values and find the area

A = L* W

A = 92.5in * 88.5in

A = 8186.25 in²

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