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Fill in the blanks (B1, B2, B3) in the equation based on the graph.(a-B1)2 + (y-B2)² = (B3)²8182=83=Blank 1:

Fill In The Blanks B1 B2 B3 In The Equation Based On The GraphaB12 YB2 B3818283Blank 1 class=

Sagot :

Given: a circle is given with center (3,-3) and equation

[tex](x-B_1)^2+(y-B_2)^2=(B_3)^2[/tex]

Find:

[tex]B_{1,\text{ }}B_{2,}B_3[/tex]

Explanation: the general equation of the circle with center (a,b) and radius r is

[tex](x-a)^2+(y-b)^2=r^2[/tex]

in the given figure the center of the circle is at (3,-3)

so the equatio of the circle becomes

[tex](x-3)^2+(y+3)^2=(3)^2[/tex]

on comparing eith the given equation we get

[tex]B_1=3,\text{ B}_2=-3\text{ and B}_3=3[/tex]

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