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How many total atoms are there in 19.3 g of hydrazine (N_{2}*H_{2})

How Many Total Atoms Are There In 193 G Of Hydrazine N2H2 class=

Sagot :

Answer:

[tex]3.87*10^{23}atoms[/tex]

Explanations:

Given the following parameters

Mass of hydrazine = 19.3 grams

Determine the moles of hydrazine

[tex]\begin{gathered} moles\text{ of N}_2H_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of N}_2H_2=\frac{19.3}{30.02928} \\ moles\text{ of N}_2H_2=0.6423moles \end{gathered}[/tex]

According to the Avogadro's constant

[tex]1mole\text{ of a substance}=6.02\times10^{23}atoms[/tex][tex]\begin{gathered} atoms\text{ of N}_2H_2=0.643\times6.02\times10^{23} \\ atoms\text{ of N}_2H_2=3.87\times10^{23}atoms \end{gathered}[/tex]

Therefore the total atoms that are there in 19.3 g of hydrazine is 3.87 * 10^23 atoms

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