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AABC is isosceles.mZA = 3x + 40 and mZC = x + 50BAmZA= [ ? 1°

AABC Is IsoscelesmZA 3x 40 And MZC X 50BAmZA 1 class=

Sagot :

ANSWER:

The value of the angle A is 55°

STEP-BY-STEP EXPLANATION:

Angles opposite equal sides are angles that are also equal.

Therefore, in this case A and C are equal angles, therefore we can do the following equation:

[tex]\begin{gathered} A=C \\ 3x+40=x+50 \end{gathered}[/tex]

Solving for x:

[tex]\begin{gathered} 3x-x=50-40 \\ 2x=10 \\ x=\frac{10}{2} \\ x=5 \end{gathered}[/tex]

Now we replace the value of x, in A and we are left with:

[tex]\begin{gathered} A=3\cdot5+40 \\ A=15+40 \\ A=55 \end{gathered}[/tex]

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