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Sagot :
Volume of empty jar 8x² + 2x - 4
Volume of water poured = 4x² - 3x + 2
More number of cubic inches that the jar can still hold= (8x² +2x - 4) -(4x²- 3x+2)
= 8x² + 2x - 4 - 4x² + 3x - 2
Rearrange
=8x² - 4x² + 2x + 3x - 4 - 2
=4x² + 5x - 6
Hence, the more number of cubic inches that the jar can still hold is
4x² + 5x - 6
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