Given:
• Distance traveled rightward = 6 m
,• Distance traveled leftward = 10 m
,• Total time, t = 30 s
Let's solve for the following:
• (1). What is the penguin’s average velocity during the chase?
To find the average velocity, apply the formula:
[tex]v=\frac{d}{t}[/tex]Where:
• v is the average velocity in m/s
,• d is the displacement
,• t is the total time in seconds.
The displacement given a 6 meters rightward move and 10 m leftward move is:
d = 6m + (-10 m) = 6m - 10m = -4 m
Thus, we have:
[tex]\begin{gathered} v=\frac{-4}{30} \\ \\ v=-0.13\text{m/s} \end{gathered}[/tex]The average velocity is -0.13 m/s.
• (2). What is the penguin’s average speed during the chase?
To find the average speed, we have:
[tex]v=\frac{d}{t}[/tex]v is the average speed in m/s
d is the total distance = 6m + 10m = 16m
t is the total time = 30 s
Thus, we have:
[tex]\begin{gathered} v=\frac{16}{30} \\ \\ v=0.53\text{ m/s} \end{gathered}[/tex]The average speed is 0.53 m/s.
ANSWER:
0. Average velocity = -0.13 m/s
,1. Average speed = 0.53 m/s