The area of the composite figure can be solved by separating the figure into 3 portions, which are 2 identical rectangles with one rectangle.
The image of the composite figure will be shown below
Let us sketch out the image of the two identical rectangles
The formula for the area(A) of a rectangle is,
[tex]A=length\times width[/tex]
where,
[tex]\begin{gathered} l=length=5m \\ w=width=2m \end{gathered}[/tex]
Therefore, the area(A1) of the two identical rectangles are
[tex]\begin{gathered} A_1=2\times(5\times2)=2\times5\times2=20m^2 \\ \therefore A_1=20m^2 \end{gathered}[/tex]
Let me sketch the second rectangle
Therefore, the area(A2) will be
[tex]\begin{gathered} A_2=3\times2=6m^2 \\ \therefore A_2=6m^2 \end{gathered}[/tex]
Hence, the area(A) of the composite figure is
[tex]\begin{gathered} A=A_1+A_2=20m^2+6m^2=26m^2 \\ \therefore A=26m^2 \end{gathered}[/tex]
Therefore, the area is
[tex]26m^2[/tex]
