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If the function fis defined by f(x) = x ^ 5 - 1 then the inverse, f ^ - 1 is defined by f ^ - 1 * (x) =

If The Function Fis Defined By Fx X 5 1 Then The Inverse F 1 Is Defined By F 1 X class=

Sagot :

Given the function:

[tex]f(x)=x^5-1[/tex]

We have that f(x) = y, so:

[tex]y=x^5-1[/tex]

Substitute x with y:

[tex]x=y^5-1[/tex]

And solve for y:

[tex]\begin{gathered} x+1=y^5-1+1 \\ x+1=y^5 \\ y=\sqrt[5]{x+1} \end{gathered}[/tex]

Answer:

[tex]\sqrt[5]{x+1}[/tex]

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