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What power is emitted by a circuit with a 9.00 volt battery and a 50.0 Ohm resistor? A)450 W B)0.00222 W C)1.62 W D)5.55 W E)0.180 W

Sagot :

Given,

Voltage, V=9 V

Resistor, R=50.0 ohm

To find

The power emitted by the battery.

Explanation

The power is:

[tex]\begin{gathered} P=\frac{V^2}{R} \\ \Rightarrow P=\frac{9^2}{50} \\ \Rightarrow P=1.62\text{ W} \end{gathered}[/tex]

Conclusion

The power is: C.1.62W

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