Answered

IDNLearn.com makes it easy to find the right answers to your questions. Find the answers you need quickly and accurately with help from our knowledgeable and dedicated community members.

Problem 12a) solve for x, 3(-2x +5) = 9(x-5), x=b) x = –27, x =

Sagot :

The given equation is

[tex]3(-2x+5)=9(x-5)[/tex]

Dividing by 3 both sides, we get

[tex]\frac{3\mleft(-2x+5\mright)}{3}=\frac{9\mleft(x-5\mright)}{3}[/tex]

[tex]-2x+5=3(x-5)[/tex]

Multiplying 3 and (x-5) as follows.

[tex]-2x+5=3\times x-3\times5[/tex]

[tex]-2x+5=3x-15[/tex]

Adding 15 on both sides, we get

[tex]-2x+5+15=3x-15+15[/tex]

[tex]-2x+20=3x[/tex]

Adding 2x on both sides, we get

[tex]-2x+20+2x=3x+2x[/tex]

[tex]20=5x[/tex]

Dividing by 5, we get

[tex]\frac{20}{5}=\frac{5x}{5}[/tex][tex]4=x[/tex]

Hence the value of x is 4.

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is your go-to source for dependable answers. Thank you for visiting, and we hope to assist you again.