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Sagot :
Let cheryl score "c", Adam score "a", Laura score "l" and Tom score "t", points.
Now, let's write equations for statements given.
Adam scores 8 more than Cheryl, so:
a = c + 8
or
c = a - 8
Laura scored twice as Adam, so:
l = 2a
Tom scores 10 less than Laura:
t = l - 10
or
t = 2a - 10
Altogether, they scored 66, so:
c + a + l + t = 66
Putting the 3 bold equations in the last one, we can solve for "a" first. Shown below:
[tex]\begin{gathered} c+a+l+t=66 \\ a-8+a+2a+2a-10=66 \\ 6a-18=66 \\ 6a=66+18 \\ 6a=84 \\ a=\frac{84}{6} \\ a=14 \end{gathered}[/tex]So,
c = a - 8
c = 14 - 8
c = 6
l = 2a
l = 2(14)
l = 28
t = 2a - 10
t = 2(14) - 10
t = 28 - 10
t = 18
So,
Adam = 14 points
Cheryl = 6 points
Laura = 28 points
Tom = 18 points
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