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005 (part 1 of 3) A 59 N object is in free fall. What is the magnitude of the net force which acts on the object? Answer in units of N.006 (part 2 of 3) What is the magnitude of the net force when the object encounters 23.4 N of air resistance? Answer in units of N.007 (part 3 of 3) What is the magnitude of the net force when it falls fast enough to encounter an air resistance of 59 N?Answer in units of N.

Sagot :

Given that weight of the object, mg= 59 N

Here, m is the mass and g is the acceleration due to gravity.

(a) The net force acting on the object is

[tex]\begin{gathered} F=mg \\ =59\text{ N} \end{gathered}[/tex]

(b) Given that object encounters air resistance of 23.4 N which acts in opposite direction of free fall.

Thus, the net force will be

[tex]\begin{gathered} F^{\prime}=\text{ mg-air resistance} \\ =59-23.4 \\ =35.6\text{ N} \end{gathered}[/tex]

(c) Given that air resistance is 59 N.

Thus the net force will be

[tex]\begin{gathered} F^{\doubleprime}=\text{ 59-59} \\ =0\text{ N} \end{gathered}[/tex]

Thus, the net forcce is zero in this case.

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