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A 5 kg mass, hung onto a spring, causes the spring to stretch 7.0 cm. What is the spring constant? What is the potential energy of the spring?

Sagot :

Given,

The mass is m=5 kg.

The extensionis d=7.0 cm

The force is

F=mg

F=5x0.07=0.35N

Thus the spring constant is:

[tex]k=\frac{F}{d}=\frac{0.35}{0.07}=\frac{5N}{m}[/tex]

The potential energy is:

[tex]U=\frac{1}{2}kd^2=\frac{1}{2}\times5\times(0.07)^2=0.012Nm^2[/tex]

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