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Writing an equation in slope intercept form for the line passing through each pair of points. (0,3) (1,-2)

Sagot :

Calculating the slope of the line with points (0,3) (1,-2)

[tex]\begin{gathered} m=\frac{y2-y1}{x2-x1}=\frac{-2-3}{1-0}=\frac{-5}{1}=-5 \\ m=-5 \end{gathered}[/tex]

With the slope and one of the points we find the y-intercept with the equation y=mx +b.

y= mx + b (m: slope , b=y-intercept)

3=-5(0) + b (Replacing m=-5 and the point (0,3))

3= 0 + b (Multiplying)

3=b

The answer is y=-5x + 3.

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