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Sagot :
Given that In five years time job will be four times as old as his son Mark and Two years ago Jon was eleven times as old as mark.
Let the age of job and mark now be x and y years old.
So, in five years the age of job will be x + 5 and the age of his son mark will be y + 5.
According to the question,
[tex]\begin{gathered} x+5=4(y+5) \\ x+5=4y+20 \\ x-4y=15 \end{gathered}[/tex]Two years ago, the age of job was x - 2 and the age of his son mark was y - 2.
So, according to the question.
[tex]\begin{gathered} x-2=11(y-2) \\ x-2=11y-22 \\ x-11y=-20 \end{gathered}[/tex]From the first equation, we have x = 4y + 15. Substitute this value in the second equation and solve:
[tex]\begin{gathered} 4y+15-11y=-20 \\ -7y=-35 \\ y=5 \end{gathered}[/tex]Substitute y = 5 in x = 4y + 15.
[tex]\begin{gathered} x=4(5)+15 \\ x=20+15 \\ x=35 \end{gathered}[/tex]Thus, the present age of job is 35 years and the present age of his son mark is 5 years.
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