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How many moles of O2 is in a 5.6 L sample of O2 measured at 250 kPa and 18°C?

Sagot :

Answer

578.66 mol

Explanation

Given:

Volume, V = 5.6 L

Temperature, T = 18° C = 18 + 273 = 291 K

Pressure, P = 250 kPa = 250000 Pa

Using the ideal gas equation, we can solve for the number of moles:

[tex]PV=\text{nRT}[/tex]

Put the given values into the ideal gas equation to get the number of moles:

[tex]\begin{gathered} 250000\times5.6=n\times8.314\times291 \\ 1400000=2419.374n \\ \text{Divide both sides by 2419.374} \\ \frac{1400000}{2419.374}=\frac{2419.37n}{2419.374} \\ n=578.66\text{ mol} \end{gathered}[/tex]

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