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(3,-4); m=6 write an equation in slope intercept form for the line through the given point with the given slope

Sagot :

y= 6x-22

Explanation

Step 1

Let

slope=6

Point (3,-4)

to find the equation in slope intercept form use

[tex]\begin{gathered} y-y_0=m(x-x_0) \\ \text{where} \\ (x_0,y_0)\text{ are the coordinates of the known point} \end{gathered}[/tex]

Step 2

Replace,

[tex]\begin{gathered} \text{the know point = (3,-4) so} \\ y-y_0=m\left(x-x_0\right) \\ y-(-4)=6(x-3) \\ y+4=6x-18 \\ \text{substract 4 in both sides} \\ y+4-4=6x-18-4 \\ y=6x-22 \end{gathered}[/tex]

I hope this helps you