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Sagot :
Solution:
Given the equation;
[tex]y=\frac{1}{4}(4^x)[/tex]We would create a table of values such that x ranges from 0 to 5;
[tex]\begin{gathered} x=0; \\ \\ y=\frac{1}{4}(4^0)=\frac{1}{4} \\ \\ (0,\frac{1}{4}) \\ \\ x=1; \\ \\ y=\frac{1}{4}(4^1)=1 \\ \\ (1,1) \\ \\ x=2; \\ \\ y=\frac{1}{4}(4^2)=4 \\ \\ (2,4) \end{gathered}[/tex]Then;
[tex]\begin{gathered} x=3; \\ \\ y=\frac{1}{4}(4^3)=16 \\ \\ (3,16) \\ \\ x=4; \\ \\ y=\frac{1}{4}(4^4)=64 \\ \\ (4,64) \\ \\ x=5; \\ \\ y=\frac{1}{4}(4^5)=256 \\ \\ (5,256) \end{gathered}[/tex]Thus, the correct table is;
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