Answered

IDNLearn.com makes it easy to find the right answers to your questions. Discover trustworthy solutions to your questions quickly and accurately with help from our dedicated community of experts.

-11. Given points (x, y) and (x2, y2), derive the two-point form of a line. , , , 10. 13. Given that a line is parallel to the x-axis through (x, y), derive the parallel to x-axis form a line.

11 Given Points X Y And X2 Y2 Derive The Twopoint Form Of A Line 10 13 Given That A Line Is Parallel To The Xaxis Through X Y Derive The Parallel To Xaxis Form class=

Sagot :

11. Given the two points (x1, y1) & (x2, y2) we will have the following line and we derivate it:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex][tex]y-y_1=m(x-x_1)\Rightarrow y=mx-mx_1+y_1[/tex]

It's derivative is:

[tex]\frac{\delta y}{\delta x}=m=\frac{y_2-y_1}{x_2-x_1}[/tex]

This is since the derivative of constants is 0 and the only variable accompanied m. This is proof that the derivative of a function can be interpreted as the slope of the function at that point.

13. If we have that the line is parallel to the x-axis and passes through the point (x1, y1), we will have that the line is a constant function, so when we derivate no matter the point, it will be equal to 0.

That is:

[tex]y=x_1[/tex][tex]\frac{\delta y}{\delta x}=0[/tex]

***Explanation:

point 11:

Since we are given two points (x1, y1) & (x2, y2), we will always have that the slope of the line that passes through those points will always have the form:

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.