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Find the half-life (in hours) of a radioactive substance that is reduced by 5 percent in 75 hours.half life = ___ include units

Sagot :

Let's list down the given information.

Time = 75 hours

Final Value = reduced by 5% = 95%

To get the half life, the formula is:

[tex]t=\frac{\ln 0.5}{k}[/tex]

Before we can get the half-life, we need to get the value of k or the decay rate first. The formula is:

[tex]k=\frac{\ln A}{t}[/tex]

where A is the final value in percentage and t = time. Since we have this information above, let's plug it in the formula and solve for k.

[tex]k=\frac{\ln0.95}{75}=-0.0006839105918[/tex]

Now that we have the value of "k", let's solve for "t" using the formula stated above as well.

[tex]t=\frac{\ln 0.5}{k}=\frac{\ln 0.5}{-0.0006839105918}=1013.51[/tex]

Hence, the half life of the radioactive substance is approximately 1,013.51 hours or 1,013 hours and 30 minutes.