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Sagot :
2.7 ,2.9, 7.2, 7.5, 8.5, 11.2,15.4, 18.3
The minimum is the smallest number in the data : 2.7
The maximum is the largest number in the data : 18.3
Next, we find the median, which is the middle number in the data when arranged from smallest to largest. There are 8 numbers, so we will average the middle 2 numbers
2.7 ,2.9, 7.2, 7.5, 8.5, 11.2,15.4, 18.3
The middle is between the 4th and 5th numbers
( 7.5 + 8.5) / 2 = 16/2 = 8
The median(Q2) is 8
To find Q1 ( the 1st quartile), we take the numbers below the mean
2.7 ,2.9, 7.2, 7.5,
and find the median of these numbers
There are 4 numbers so the middle is between the 2nd and 3rd numbers
2.7 , 2.9, 7.2, 7.5,
(2.9+7.2) /2 =5.05
Q1 = 5.05
We will do the same process for Q3, which is the third quartile. We will use the numbers above the median
8.5, 11.2,15.4, 18.3
( 11.2 + 15.4) /2 =13.3
Q3 = 13.3
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