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Sagot :
Given:
• Mass, m = 78.0 kg
,• Acceleration = 1.25 m/s²
Let's find the normal force.
To find the normal force, apply the formula for Newton's second law:
[tex]\begin{gathered} \Sigma F_y=ma_y \\ \\ F-mg=-ma \end{gathered}[/tex]Where:
m is the mass of the person = 78.0 kg
a is the acceleration = 1.25 m/s²
g is acceleration due to gravity = 9.8 m/s²
F is the normal force
Thus, we have:
[tex]\begin{gathered} F=mg-ma \\ \\ F=m(g-a) \\ \\ F=78(9.8-1.25) \end{gathered}[/tex]Solving further:
[tex]\begin{gathered} F=78(8.55) \\ \\ F=666.9\text{ N} \end{gathered}[/tex]The reading on the scale will be in kilograms.
Hence, we have:
[tex]m=\frac{N}{g}=\frac{666.9}{9.8}=68.1\text{ kg}[/tex]Therefore, the reading on the scale will be 68.1 kg or 666.9 N
ANSWER:
666.9 N
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