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What is the slope of the line given by the following equation?  13x + 4y = 52

Sagot :

Given the linear equation;

[tex]13x+4y=52-----1[/tex]

We can find the slope by comparing the above equation with the general equation of a line. This can be seen below.

[tex]y=mx+c------2[/tex]

Where m is the slope of the equation

We then make y the subject of the formula in equation one

[tex]\begin{gathered} 13x+4y=52 \\ \text{subtract 13x from both sides} \\ 13x-13x+4y=52-13x \\ 4y=52-13x \\ \text{Divide both sides by 4} \\ \frac{4y}{4}=\frac{52}{4}-\frac{13x}{4} \\ y=13-\frac{13x}{4} \end{gathered}[/tex]

By comparison,

[tex]m=-\frac{13}{4}[/tex]

Answer: The slope of the equation is

[tex]\text{slope}=-\frac{13}{4}[/tex]

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