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Ronald was 1.5 times olderthan Megan. If Ronald was 27years old, how old is Megan?Write an equation to solve.

Sagot :

Solution:

Let x represent Ronald's age, and y represent Megan's age.

Thus,

[tex]\begin{gathered} x\Rightarrow Ronald^{\prime}s\text{ age} \\ y\Rightarrow Megan^{\prime}s\text{ age} \end{gathered}[/tex]

Given that Ronald was 1.5 times older than Megan, we have the equation to be represented

[tex]x=1.5y\text{ ---- equation 1}[/tex]

If Ronald was 27 years old, we have

[tex]x=27[/tex]

Substituting the value of 27 for x into equation 1, we have

[tex]\begin{gathered} 27=1.5y \\ solve\text{ for y by dividing both sides by the coefficient of y,} \\ \frac{27}{1.5}=\frac{1.5y}{1.5} \\ \Rightarrow y=18 \end{gathered}[/tex]

This implies that Megan's age is

[tex]18\text{ years}[/tex]

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