Answered

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A box of mass m = 2 kg is kicked on a rough horizontal plane with an initial velocity v_0 . If the net work done on the crate during its entire motion , until it comes to rest , is -36 J , then the initial velocity v_0 of the box is equal to :

A Box Of Mass M 2 Kg Is Kicked On A Rough Horizontal Plane With An Initial Velocity V0 If The Net Work Done On The Crate During Its Entire Motion Until It Comes class=

Sagot :

Given:

The mass of the box is m = 2 kg

The work done is W = -36 J

The final velocity of the object is

[tex]v_f=\text{ 0 m/s}[/tex]

To find the initial velocity of the box.

Explanation:

The initial velocity of the box can be calculated as

[tex]\begin{gathered} Work\text{ done = change in kinetic energy} \\ W=\frac{1}{2}m(v_f^2-v_o^2) \\ -36=\frac{1}{2}\times2(0^2-v_o^2) \\ -v_{_0}^2=-36 \\ v_o=6\text{ m/s} \end{gathered}[/tex]

Hence, the initial velocity of the box is 6 m/s.

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