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A 0.7kg ball Is thrown and accelerated by 62 m/s. How much force is applied to it? Round your answer to the nearest whole number

Sagot :

Given:

the mass of the ball is m=0.7 kg.

The acceleration in the ball is

[tex]a=62\text{ m/s}^2[/tex]

Required: the force applied on the ball

Explanation:

The force is given by

[tex]F=ma[/tex]

here, F is force, m is the mass, and a is the acceleration.

Plugging all the values in the above relation, we get:

[tex]\begin{gathered} F=0.7\text{ kg}\times62\text{ m/s}^2 \\ F=43.4\text{ N} \\ F\approx43\text{ N} \end{gathered}[/tex]

Thus, the force on the ball is 43 N.

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