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ANSWER
[tex]A)\frac{2}{7}[/tex]EXPLANATION
There are 7 days in a week.
The probability that a chosen day of the week is Wednesday or Saturday is the sum of the probability that the day is a Wednesday and the probability that the day is a Saturday.
Since there is only one Wednesday in a week, the probability that the day is a Wednesday is:
[tex]P(W)=\frac{1}{7}[/tex]The same rule applies for Saturday:
[tex]P(S)=\frac{1}{7}[/tex]Therefore, the probability that the day is a Wednesday or a Saturday is:
[tex]\begin{gathered} P(W-or-S)=\frac{1}{7}+\frac{1}{7} \\ P(W-or-S)=\frac{2}{7} \end{gathered}[/tex]
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