Answered

IDNLearn.com offers a seamless experience for finding and sharing knowledge. Get the information you need quickly and accurately with our reliable and thorough Q&A platform.

Determine the equation of the line that passes through the point (-1, 2) and isperpendicular to the line y = -2.

Determine The Equation Of The Line That Passes Through The Point 1 2 And Isperpendicular To The Line Y 2 class=

Sagot :

[tex]y=-\frac{1}{2}x+\frac{3}{2}[/tex]

1) In this question, let's find the equation, using the point-slope formula:

[tex](y-y_0)=m(x-x_0)[/tex]

2) Notice that since we want a perpendicular line we can write a perpendicular line to y=2, as x=-1/2 for -1/2 is the opposite and reciprocal to 2 (the necessary condition to get a perpendicular line).

So, the slope of that perpendicular line is -1/2

3) Let's plug into that Point-Slope formula, the slope m= -1/2 and the point:

[tex]\begin{gathered} (y-2)=-\frac{1}{2}(x+1) \\ y-2=-\frac{1}{2}x-\frac{1}{2} \\ y=-\frac{1}{2}x-\frac{1}{2}+2 \\ y=-\frac{1}{2}x+\frac{3}{2} \end{gathered}[/tex]

4) Thus, the answer is:

[tex]y=-\frac{1}{2}x+\frac{3}{2}[/tex]

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.