Join the IDNLearn.com community and get your questions answered by experts. Our experts provide timely, comprehensive responses to ensure you have the information you need.

One number is 22 more than another. Their product is – 121.Step 1 of 2: Set up an equation to solve the given word problem. Let x be the smaller number.Answer# KeypadKeyboard ShortcutsO x + x + 22 = - 121O x(22x) = - 121O x(x + 22)- 121O x(x – 22)- 121

One Number Is 22 More Than Another Their Product Is 121Step 1 Of 2 Set Up An Equation To Solve The Given Word Problem Let X Be The Smaller NumberAnswer KeypadKe class=
One Number Is 22 More Than Another Their Product Is 121Step 1 Of 2 Set Up An Equation To Solve The Given Word Problem Let X Be The Smaller NumberAnswer KeypadKe class=

Sagot :

Step 1

Let it be:

• x: The smaller number.

,

• x + 22: The larger number.

The product of both numbers is:

[tex]x(x+22)[/tex]

Since the product of both numbers is -121, we can write:

[tex]x(x+22)=-121[/tex]

The word 'is' is represented by the symbol =.

Therefore, the equation to solve the given word problem is:

[tex]x(x+22)=-121[/tex]Step 2

To find the numbers, we solve the previous equation.

[tex]\begin{gathered} x(x+22)=-121 \\ \text{ Apply the distributive property on the left side} \\ x\cdot x+22\cdot x=-121 \\ x^2+22x=-121 \\ \text{ Add }121\text{ from both sides} \\ x^2+22x+121=-121+121 \\ x^2+22x+121=0 \end{gathered}[/tex]

Now, we can factor the expression on the left side using the perfect square trinomial rule.

[tex]a^2+2ab+b^2=(a+b)^2[/tex]

Then, we have:

[tex]\begin{gathered} x^2+22x+121=0 \\ x^2+2\cdot11\cdot x+11^2=0 \\ (x+11)^2=0 \\ \text{ Apply square root to both sides of the equation} \\ \sqrt[]{(x+11)^2}=\sqrt[]{0} \\ x+11=0 \\ \text{ Subtract 11 from both sides} \\ x+11-11=0-11 \\ x=-11 \end{gathered}[/tex]

Finally, we find the another number.

[tex]\begin{gathered} x+22=-11+22 \\ x+22=11 \end{gathered}[/tex]

Therefore, the numbers are -11 and 11.