A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they

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03-11-2022
Physics

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A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they

Sagot :

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RihaH704530idn RihaH704530idn · Answer 1 · 2022-11-03T17:42:14-04:00

The expression for the gravitational force between two bodies is given by:

[tex]F=G\frac{m_1m_2}{r^2}[/tex]

where,

G: Cavendish's constant = 6.67*10-11Nm^2/kg^2

m1 = 3.0kg

m2 = 14kg

Solve the equation above for r:

[tex]\begin{gathered} r=\sqrt{\frac{Gm_1m_2}{F}} \\ r=\sqrt[]{\frac{(6.67\cdot10^{-11}\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^{-10}N}} \\ r\approx1.67m \end{gathered}[/tex]

Hence, the distance between the dog and the car is approximately 1.67m

Sagot :

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